Two identical cars (m = 1350 kg) are traveling at the same speed of 28.1 m/s. They are moving in the directions shown in the drawing. What is the magnitude of the total momentum of the two cars?

Answer 1

p=mv
First find the resultant of the two velocity vectors by using the Pythagorean theorem. Since the cars are identical, the velocities are the same.

find the sq. root of (28.1^2)+(28.1^2)

you should get 39.7394011 after you find the sq. root.
multiply your answer by the mass:
39.7394011*1350 and you should get your answer.

hope this helped:)

Answer 2

I got 44.74651644 for the resultant vector car a is going 60 degrees from the positive y axis going left. The other is going north east 30 degrees from the y axis. I'm assuming the deprzwing is the same, but both answers are incorrect.

Answer 3

My bad. I didnt read closely enough. Finding the square root of the velocity squared plus the velocity squared and multiplying that by the mass did get me the right answer