d1 = distance hiker P traveled,
d2 = distance hiker Q traveled,
d1 + d2 = 20 km.
4t +6t = 20 km,
10t = 20,
t = 2 h = time they met.
4t = 4 * 2 = 8 km = d1.
6t = 6 * 2 = 12 km = d2.
Two hikers begin walking towards each other from an initial distance of 20 km
apart. Hiker P averages 4 km/h while hiker Q averages 6 km/h. When and where do
they meet?
1 answer