1.A hiker started to walk from her campsite heading east with a velocity of 5 m\s after 6 seconds, she attained a velocity of 7 m\s. What is the average velocity of the hiker? What is the hiker’s acceleration? If the hiker continues walking for another 60 seconds, how far east can she go?

Answer 1

a. avgvelocity=(final+starting)/2= 6m/s

acceleration=changevelocity/time=1/3 m/s^2

distance=distance first six seconds+distance for last 54 seconds
= avgvelocity*6+7*54=36m+378m

Answer 2

456