east components
2880 cos 42 = 2140
south components
2880 sin 42 + 4360 = 6287
magnitude = sqrt (2140^2+6287^2)
tan (angle) = 6287/2140
Two forces are applied to a tree stump to pull it out of the ground. Force A has a magnitude of 2880 newtons (N) and points 42.0 ° south of east, while force B has a magnitude of 4360 N and points due south. Using the component method, find the (a) magnitude and (b) direction of the resultant force A + B that is applied to the stump. Specify the direction as a positive angle with respect to due east.
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