Two forces are applied to a block of mass MM=12.0 kg that sits on a horizontal, frictionless table. One force F⃗ 1F→1 has a magnitude of 10.0 N and is directed at an angle θ1 equal to 37.0° from the xx direction as labeled in the figure below. As a result of the forces, the block experiences an acceleration a equal to 0.440 m/s2 in the xx direction only. What is the x component of the sum of the other forces acting on the block? (Express your answer to three significant figures.) 2)

Question

Two forces are applied to a block of mass MM=12.0 kg that sits on a horizontal, frictionless table. One force F⃗ 1F→1 has a magnitude of 10.0 N and is directed at an angle θ1 equal to 37.0° from the xx direction as labeled in the figure below. As a result of the forces, the block experiences an acceleration a equal to 0.440 m/s2 in the xx direction only. What is the x component of the sum of the other forces acting on the block? (Express your answer to three significant figures.) 2)
What is the yy component of the sum of the other forces acting on the block? (Express your answer to three significant figures.)

Neam · Answer

Part 1 F = 12*0.44 = 5.28 N Therefore, 10cos37 + F2 = 5.28 F2 = -2.71 N

Neam · Answer

I cant figure out Part 2. HELP

Guppy · Answer

Whats up Neam!? I was gonna respond to ur post but I see that its a little too late now! I hope you ended up doing well in physics 2 years ago!