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Questions (1)
Two forces are applied to a block of mass MM=12.0 kg that sits on a horizontal, frictionless table. One force F⃗ 1F→1 has a
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Answers (3)
Centripetal force f = mV²/r = mrω² ω is angular velocity in radians/sec 1 radian/sec = 9.55 rev/min m is mass in kg r is radius of circle in meters V is the tangental velocity in m/s f is in Newtons m = w/g = 800/9.8 = 81.6 kg F = mV²/r = 81.6(25)² /
I cant figure out Part 2. HELP
Part 1 F = 12*0.44 = 5.28 N Therefore, 10cos37 + F2 = 5.28 F2 = -2.71 N
