Neam

Two forces are applied to a block of mass MM=12.0 kg that sits on a horizontal, frictionless table. One force F⃗ 1F→1 has a magnitude of 10.0 N and is directed at an angle θ1 equal to 37.0° from the xx direction as labeled in the figure below. As a result...

Part 1 F = 12*0.44 = 5.28 N Therefore, 10cos37 + F2 = 5.28 F2 = -2.71 N

I cant figure out Part 2. HELP

Centripetal force f = mV²/r = mrω² ω is angular velocity in radians/sec 1 radian/sec = 9.55 rev/min m is mass in kg r is radius of circle in meters V is the tangental velocity in m/s f is in Newtons m = w/g = 800/9.8 = 81.6 kg F = mV²/r = 81.6(25)² / (150...