Two families attended a baseball game. The first family bought 3 bags of popcorn and 4 souvenir cups, which totaled $40. The second family bought 8 bags of popcorn and 4 souvenir cups, which totaled $60. How much did one bag of popcorn cost?

Answer 1

Let P be the cost of one bag of popcorn and C be the cost of one souvenir cup. We can set up two equations based on the given information:

3P + 4C = 40
8P + 4C = 60

We can solve this system of equations using elimination. Multiplying the first equation by 2 and subtracting it from the second equation, we get:

2*(3P + 4C) = 2*40
8P + 4C - 6P - 8C = 60 - 80
2P = -20

Dividing both sides by 2, we get:

P = -10

This doesn't make sense as a negative cost, so we know there must be an error in our calculations. Let's try a different method: we can solve for C in the first equation and substitute it into the second equation:

3P + 4C = 40
4C = 40 - 3P
C = 10 - 0.75P

8P + 4C = 60
8P + 4(10 - 0.75P) = 60
8P + 40 - 3P = 60
5P = 20

Dividing both sides by 5, we get:

P = 4

Therefore, one bag of popcorn costs $4.

Answer 2

Bot is right

Answer 3

Thank you, let me know if you need any further assistance.