they close the distance at 32 mph (128/4)
x + x/3 = 4x / 3 = 32 mph
Two cyclists, 128 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
2 answers
Wrong. It can't be 32miles per hour as x 4 hrs that is the full 128 miles. What happened to the slower cyclist?
Distance = speed x time
Let s stand for cylcist 1 speed. Therefore cyclist 2 speed must be 3s.
The equation then looks like this
128 = 4s x 4
128 = 16s
8 = s
so the speed of the slower cyclist is 8 m/h and since cylist two is 3x as fast his speed must be 24m/h.
test:
1) 4 hrs x 8 miles = 32 miles
2) 4 hrs x 24 miles = 96 miles
96 + 32 = 128 miles.
128 = 4s x 4
Distance = speed x time
Let s stand for cylcist 1 speed. Therefore cyclist 2 speed must be 3s.
The equation then looks like this
128 = 4s x 4
128 = 16s
8 = s
so the speed of the slower cyclist is 8 m/h and since cylist two is 3x as fast his speed must be 24m/h.
test:
1) 4 hrs x 8 miles = 32 miles
2) 4 hrs x 24 miles = 96 miles
96 + 32 = 128 miles.
128 = 4s x 4
2 answers