Two cyclists, 36 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

Answer 1

Both riders ride for 2 hours

add up their distances to be 36

distance = speed*time

2s + 2*2s = 36
6s=36
s=6

slow rider rides 2hrs*6mph = 12 mi
fast rider rides 2hrs*12mph = 24mi