two collinear harmonic oscillation x1=8sin(100pie(t)) and x2=12sin(96pie(t)) are superposed.calculate the value of time when the amplitude of the resultant oscillation will be *maximum and minimum?

Answer 1

Look mainly at the low "beat" frequency.
4sin96pit + 8(sin 100pit +sin99pit)
4 sin96pit +16 sin100pitcos4pit
saying 199/2 is about 100
that is about
4 sin 100 pi t [1+ 4cos 2 pi t]

the low beat frequency is max when
2 pi t = 0, 2pi, etc
min when 2 pi t = pi/2, pi/2 + 2 pi etc

Answer 2

Solution of ignou physics