Question
In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression
x = 4.7 cos ( 4t + π/6 )
where x is in centimeters and t is in seconds. Find the period of the motion.
x = 4.7 cos ( 4t + π/6 )
where x is in centimeters and t is in seconds. Find the period of the motion.
Answers
when 4 t = 2 pi we have gone around the circle from t = 0
so
4 T = 2 pi
T = 2 pi / 4 = pi/2
so
4 T = 2 pi
T = 2 pi / 4 = pi/2
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