Asked by Nuwaya
A piston in a car engine has a mass of 0.75 kg and moves with motion wich was approximately simple harmonic. If the amplitude of zis oscillation is 10 cm and z max. safe operating speed of z engine is 6000 rev. per min. Calculate:
a. Max acceleration of z piston
b. Max.speed of the piston
c. The max. Force acting on the piston
a. Max acceleration of z piston
b. Max.speed of the piston
c. The max. Force acting on the piston
Answers
Answered by
drwls
6000 rpm = 628.3 radians/sec
Call that angular frequency "w"
Maximum acceleration = (Amplitide)*w^2
= 0.10 m * w^2 = 39480 m/s^2
Maximum velocity = (Amplitude)*w = 62.83 m/s.
Max force = (Mass)*(max acceleration)
Call that angular frequency "w"
Maximum acceleration = (Amplitide)*w^2
= 0.10 m * w^2 = 39480 m/s^2
Maximum velocity = (Amplitude)*w = 62.83 m/s.
Max force = (Mass)*(max acceleration)
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