Two children with masses of 18 kg and 36 kg are sitting on a balanced seesaw. If the heavier child is sitting 0.45 m from the center, at what distance from the center is the lighter child sitting?

Question

Two children with masses of 18 kg and 36 kg are sitting on a balanced seesaw. If the heavier child is sitting 0.45 m from the center, at what distance from the center is the lighter child sitting?
Answer in units of m.   Please help !!!

Steve · Answer

mass * distance must be equal, so 18x = 36*0.45

Anonymous · Answer

.9 m

Roger · Answer

mass * distance needs to be equivalent, 18x = 36*.45 = .9m