Asked by yanna
Two children with masses of 24 and 31 kg are sitting on a balanced seesaw. If the lighter child is sitting 3 m from the center, where is the heavier child sitting?
Answers
Answered by
Anonymous
Tcw=Tccw
Fsind=Fsind
(24kg)(3m)=(31kg)(x-3)
Gravity (g) on both sides of equation and cancel.
Solve for x:
72=31x-39
111=31x
X=3.6m
Fsind=Fsind
(24kg)(3m)=(31kg)(x-3)
Gravity (g) on both sides of equation and cancel.
Solve for x:
72=31x-39
111=31x
X=3.6m
Answered by
R_scott
the heavier child has to be closer to the center , not farther away
(24 kg) * (3 m) = (31 kg) * (x m)
(24 kg) * (3 m) = (31 kg) * (x m)
Answered by
Anonymous
That is correct.
Tcw=Tccw
Fsind=Fsind
(24kg)(3m)=(31kg)(x)
Gravity (g) on both sides of equation and cancel.
Solve for x:
72=31x
72/31=x
X=2.3m
Tcw=Tccw
Fsind=Fsind
(24kg)(3m)=(31kg)(x)
Gravity (g) on both sides of equation and cancel.
Solve for x:
72=31x
72/31=x
X=2.3m
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