Two charges separated by one meter exert 1 Newton forces on each other. If the magnitude of each charge is doubled, the force on each charge is ______ Newtons.

Question

Thanks!

Answer 1

Coulomb's Law is:
F = kQ1*Q2 / d^2
k is a constant

Let's represent each charge as "q"
then the intial force F1 is:
F1 = k*q*q / 1^2 = kq^2

doubling the charge, the new force, F2, is:
F2 = k(2q)(2q) / 1^2 = 4kq^2

F2 is how many times bigger than F1?

Answer 2

4 times bigger - so I think the answer would be 4 Newtons.

Answer 3

4 newtons

Answer 4

69 hehe