Two cars are travelling at adjacent highway lanes in the same direction . Car B is stopped by car A which travels at 15km/hr. Then 2 seconds later car B starts and accelerate at a constant rate of 3 meter per seconds square . Determine when and where car B will overtake car A

Question

Determine the speed of car B at that time

Answer 1

time for car a is t+2
time for car b is t

distance car a
= (15000 m/3600 s)(t+2)

distance car b = (1/2)(3)t^2

so when does car a travel the same distance as car b?

(150/36)(t+2) = (3/2) t^2

solve quadratic, use the t that makes sense :)

speed of b = 3 t