To solve the equation \( 3(r + 10) + 3r = 282 \), we start by distributing the 3:
\[ 3r + 30 + 3r = 282 \]
Now, combine the like terms:
\[ 6r + 30 = 282 \]
Next, we subtract 30 from both sides:
\[ 6r = 252 \]
Now, divide both sides by 6 to solve for \( r \):
\[ r = 42 \]
The rate of the second bus is \( r = 42 \) mph.
Thus, the correct answer is:
r = 42 mph.