Two buses start at the same point and travel in opposite directions. The first bus travels 10 miles per hour faster than the second bus. In 3 hours, the buses are 282 miles apart. Use the formula below to determine the rate of the second bus 3(r + 10) + 3r = 282 (1 point) r = 21mph; r = 30mph; r = 45mDh; r = 42mph

1 answer

To determine the rate of the second bus, we can start by analyzing the given equation and the information provided.

Let \( r \) be the rate of the second bus in miles per hour. Then, the rate of the first bus is \( r + 10 \) miles per hour.

After traveling for 3 hours, the distance each bus has traveled can be expressed as follows:

  • Distance traveled by the second bus = \( 3r \)
  • Distance traveled by the first bus = \( 3(r + 10) \)

According to the problem, the total distance between the two buses is 282 miles. We can set up the equation:

\[ 3(r + 10) + 3r = 282 \]

Now, we can simplify and solve the equation:

\[ 3(r + 10) + 3r = 282 \]

Expanding the left side:

\[ 3r + 30 + 3r = 282 \]

Combining like terms:

\[ 6r + 30 = 282 \]

Subtracting 30 from both sides:

\[ 6r = 252 \]

Dividing both sides by 6:

\[ r = 42 \text{ mph} \]

Thus, the rate of the second bus is 42 mph.

The correct answer from the options provided is r = 42 mph.