Question

Two boys A and B are at two diametrically opposite points on a circle. At one
instant the two start running on the circle; A anticlockwise with constant speed v
and B clockwise with constant speed 2v. In 2 minutes, they pass each other for
the first time. How much later will they pass each other for the second time?

Answer 1

let the distance travel by both be a&b
a has a distance of d1 like wise b
speed=distanc/time
d1=2v
d2=4v
total distance
d1+d2=180
2v+4v=180
6v=180
v=30
d1=2*30
d1=60
d2=4*20
d2=120
now start u get u starting

not that there meet at same point so now calculate the time they will trave in there various direction
time=distance/velocity
but they but move at a standard velocity

Answer 2

distancetraveled=2V*t+V*t
PIr=3V*2
V=PIr/6

now for the second passing, the distance will be twice as far allthe way around, or 2PIr
distance traveled=v*t+2vt
2PI r=3Pir/6 * t
t=4 minutes