To solve for the force that the 7 kg bowling ball exerts on the 4 kg bowling ball during a collision, we can use Newton's second law, which states that \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
Given:
- Mass of the first ball, \( m_1 = 7 , \text{kg} \)
- Mass of the second ball, \( m_2 = 4 , \text{kg} \)
- Acceleration \( a = 1.875 , \text{m/s}^2 \)
According to Newton's third law of motion, the force exerted by the first ball on the second ball is equal in magnitude and opposite in direction to the force exerted by the second ball on the first ball.
We can calculate the force exerted by the first ball (7 kg) as follows:
\[ F = m_1 \times a \]
Substituting the known values:
\[ F = 7 , \text{kg} \times 1.875 , \text{m/s}^2 = 13.125 , \text{N} \]
The force is directed to the right, as the problem states that the first ball is rolling to the right.
Thus, the force that the 7 kg bowling ball exerts on the 4 kg bowling ball is 13.125 N to the right.
Correct answer: 13.125 N to the right
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