Two bowling balls of different masses collide while accelerating at 1.875 m/s 2

Question

. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses

3.73 N to the right
3.73 N to the right

13.125 N to the right
13.125 N to the right

8.875 N to the right
8.875 N to the right

7.5 N to the left

Answer 1

To find the force that the 7 kg bowling ball exerts on the 4 kg bowling ball, we can use Newton's second law, which states that \( F = m \cdot a \).

We know that the acceleration \( a \) is \( 1.875 , \text{m/s}^2 \). Now we can calculate the force exerted on the 4 kg bowling ball due to the acceleration.

The force exerted by the 7 kg bowling ball on the 4 kg bowling ball is calculated as follows:

\[ F = m \cdot a \]

For the 4 kg bowling ball:

\[ F = 4 , \text{kg} \cdot 1.875 , \text{m/s}^2 \]

Calculating that gives:

\[ F = 7.5 , \text{N} \]

Since the 4 kg ball is rolling to the left, the force exerted on it by the 7 kg ball will be to the left as well.

Thus, the correct answer is:

7.5 N to the left.