Two bowling balls of different masses collide while accelerating at 1.875 m/s^2

. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses

3.73 N to the right
3.73 N to the right

7.5 N to the left
7.5 N to the left

8.875 N to the right
8.875 N to the right

13.125 N to the right

1 answer

To find the force exerted by the 7 kg ball on the 4 kg ball, we can use Newton's second law, which states that force equals mass times acceleration (F = m*a).

First, let's calculate the acceleration exerted by the 7 kg ball on the 4 kg ball. Since both balls are accelerating, the total acceleration is the sum of their individual accelerations, which are equal in magnitude but opposite in direction.

So, the total acceleration is 1.875 m/s^2 to the left (since the 4 kg ball is moving to the left).

Now, we can calculate the force exerted by the 7 kg ball on the 4 kg ball by using the second law.

F = m*a
F = (4 kg) * (-1.875 m/s^2)
F = -7.5 N

Since the force is negative, it means that the force exerted by the 7 kg ball on the 4 kg ball is directed to the left.

Therefore, the correct answer is:
7.5 N to the left