Two bowling balls of different masses collide while accelerating at 1.875 m/s^2

Question

. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses

7.5 N to the left
7.5 N to the left

8.875 N to the right
8.875 N to the right

13.125 N to the right
13.125 N to the right

3.73 N to the right

Answer 1

To determine the force exerted by the 7 kg bowling ball on the 4 kg bowling ball, we can use Newton's second law of motion, which states that \( F = ma \) (force equals mass times acceleration).

Both balls are accelerating at \( 1.875 , \text{m/s}^2 \).

1. Calculate the force exerted by the 7 kg bowling ball:

   \[ F_{7kg} = m \cdot a \] \[ F_{7kg} = 7, \text{kg} \cdot 1.875, \text{m/s}^2 \] \[ F_{7kg} = 13.125, \text{N} \]

Since the 7 kg bowling ball is moving to the right, the force it exerts on the 4 kg bowling ball will also be to the right.

Thus, the answer is 13.125 N to the right.