The tension in the rope connecting the blocks is equal to the component of weight up the plane, Wup.
Tension = Wup = wsinTheta
The tension in the rope connecting block A to the wall is equal to the sum of the normal components of weight of both blocks, Wnormal.
Tension = Wnormal = 2wcosTheta
Two blocks each with weight w are held in place on a frictionless incline. In terms of w ans the angle theda of the incline, calculate the tension in a) the rope connecting the blocks; b) the rope that connects block A to the wall?
a) it was wsin(theda)
b) it was 2wsin(theda)
how should I have gotten these answers?
What is the component of weight of each block up the incline? ans: wsinTheta.
Break up the downward force of weight of each block into components up the plane, and normal to it.
Wnormal= wcosTheta
Wup= wsinTheta.
Make up a vector diagram to show this, I am certain it is in your text.
1 answer
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