Two blocks are arranged as shown. The pulley can be considered to be massless, and friction is negligible. M1 is four times more massive than M2.
M1--->0(Pulley)
V
V (down direction)
V
M2
If the system is released from rest, how far will M1 travel in 0.523 s?
2 answers
M2 is supposed to be hanging down from the pulley
The pulling force is M2*g
The moving mass is (M1+M2)
F=ma
M2*g=(M1+M2)a
solve for a
d=1/2 a t^2
The moving mass is (M1+M2)
F=ma
M2*g=(M1+M2)a
solve for a
d=1/2 a t^2
0 answers