Two archers shoot arrows in the same direction from the same place with the same initial speeds, but at different angles. One shoots at 45 degres above the horizontal, while the other shoots at 60 degrees. If the arrow launched at 45 degrees lands 225 from the archer, how far apart are the two arrows when they land?

Question

Two archers shoot arrows in the same direction from the same place with the same initial speeds, but at different angles. One shoots at 45 degres above the horizontal, while the other shoots at 60 degrees. If the arrow launched at 45 degrees lands 225  from the archer, how far apart are the two arrows when they land?

drwls · Answer

The range X is related to the speed V and launch angle A by X = (V^2/g) sin(2A) For a 45 degree launch X = 225 = V^2/g Use that to compute V, and then X for the other launch angle.

Anonymous · Answer

30