Two archers shoot arrows in the same direction from the same place with the same initial speeds, but at different angles. One shoots at 45.0degrees above the horizontal, while the other shoots at 60.0 degrees.If the arrow launched at 45.0 lands 225 from the archer, how far apart are the two arrows when they land? (You can assume that the arrows start at essentially ground level.)

Question

Two archers shoot arrows in the same direction from the same place with the same initial speeds, but at different angles. One shoots at 45.0degrees above the horizontal, while the other shoots at 60.0 degrees.If the arrow launched at 45.0 lands 225  from the archer, how far apart are the two arrows when they land? (You can assume that the arrows start at essentially ground level.)

Kara · Accepted Answer

thanks so much

drwls · Answer

(V^2/g)sin 90 = 225 m Solve for V. Note that sin 90 = 1. (Twice the launch angle appears in the formula) Then solve (V^2/g)(sin 90 - sin120) = X to get X, the distance between them.