Two airplanes leave an airport at the same time. one travels in the direction of 38 degrees at 140mph and the other travels in the direction of 350 degrees at 180mph. After two hours, how far apart are they? Thanks

Answer 1

Plane #1:
d1 = 140mi/h[38o] * 2h = 280mi/h[38o]

Plane #2:
d2 = 180mi/h[350o] * 2h = 360mi[350]

d = d2-d1 = 360[350o] - 280[38o]

X = 360*Cos350 - 280*Cos38 = 134 mi
Y = 360*sin350 - 280*sin38 = -235 mi

D^2 = X^2 + Y^2 = 134^2 + (-235)^2 = 73,181
D = 270.5 Miles apart.