Think of a right triangle. The airport is the vertex of the right angle. Plane A is 70 miles north (Straight up). Plane B is 168 miles East (Straight right). From plane A to B would be side C of the right triange.
C^2 = A^2 + B^2
C = sqrt (A^2 + B^2)
C = sqrt (70^2 + 168^2)
C = sqrt (33124)
C = 182 miles
2 planes leave the airport at the same time. Minutes later plane A is 70 miles due north of the airport. Plane B is 168 miles due East of the airport. How far apart are the 2 airplanes.
?
I think 98 miles apart. Is that right?
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