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Two 95.0 W (120 \rm V) lightbulbs are wired in series, then the combination is connected to a 120 V supply How much power is di...Asked by ananomyus
Two 200 W (120 V) lightbulbs are wired in series, then the combination is connected to a 120 V supply. How much power is dissipated by each bulb?
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Answered by
Henry
All calculations are done with the assumption that the resistance of the light bulbs remain constant.
P = E^2/R.
200 = 120^2/R,
R = 72 Ohms.
P = 60^2/72 = 50 Watts = Power dissipated by each bulb.
P = E^2/R.
200 = 120^2/R,
R = 72 Ohms.
P = 60^2/72 = 50 Watts = Power dissipated by each bulb.
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