Asked by Mitchell

Two 95.0 W (120 \rm V) lightbulbs are wired in series, then the combination is connected to a 120 V supply How much power is dissipated by each bulb?

14 years ago

Answered by Writeacher

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14 years ago

Answered by bobpursley

Figure the resistance of each bulb.

Power= V^2/R
R= 120^2/95

Now that two are in series

power total= V^2/2R= 95/2

power each= 95/4 watts.

14 years ago

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