Two 200 W (120 V) lightbulbs are wired in series, then the combination is connected to a 120 V supply. How much power is dissipated by each bulb?

Answer 1

in normal operation of a bulb
200 Watts = V^2/R = 120^2/R
so R = 72 Ohms

now we have two in series so V = 120/2 = 60 volts

again watts power = V^2/R = 60^2/72
= 50 watts

Answer 2

There is a hot-air balloons festival in system spring. seventh-two balloon registered