Asked by ananomyus

Two 200 W (120 V) lightbulbs are wired in series, then the combination is connected to a 120 V supply. How much power is dissipated by each bulb?
Answered by Damon
in normal operation of a bulb
200 Watts = V^2/R = 120^2/R
so R = 72 Ohms

now we have two in series so V = 120/2 = 60 volts

again watts power = V^2/R = 60^2/72
= 50 watts
Answered by Cinthia
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