Triangle MNO

is translated up 5 units and left 2 units. Point N
is located at (0, −6)
. What are the coordinates of N′
?(1 point)
Responses

(−2,−11)
left parenthesis negative 2 comma negative 11 right parenthesis

(5,−8)
left parenthesis 5 comma negative 8 right parenthesis

(2,−1)
left parenthesis 2 comma negative 1 right parenthesis

(−2,−1)

1 answer

To find the new coordinates of point \( N' \) after translating point \( N \) at (0, -6) up 5 units and left 2 units, follow these steps:

  1. Translate up 5 units: This means adding 5 to the y-coordinate: \[ -6 + 5 = -1 \] This gives the new y-coordinate as -1.

  2. Translate left 2 units: This means subtracting 2 from the x-coordinate: \[ 0 - 2 = -2 \] This gives the new x-coordinate as -2.

Thus, the new coordinates of \( N' \) are: \[ (-2, -1) \]

The correct response is: \[ (-2, -1) \]