Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold.

Question

Find the mass of the gold salt that forms when a 73.0 -g mixture of equal masses of all three reactants is prepared.

Answer 1

equal masses means 73.0/3 = 24.33 g each.
Calculate moles each. moles = grams/molar mass.
Using the coefficients in th balanced equation, convert each to moles of the salt. The smallest value will be the amount of salt that forms and that reagent will be the limiting reagent. Use that value to convert to grams. g = moles x molar mass.

Answer 2

Coool. Beans

Answer 3

this was a little helpful but no exactally what i was looking for