Town Y and Town Z were 512 km apart. Car A left Town Y for Town Z at a speed of 32km/h. An hour later car B left Town Z for Town Y at twice of car A ‘s speed. How long would it take for the two cars each other after car A left Town Y

Answer 1

distance = speed * time, so
32t + 2*32(t-1) = 512
now solve for t.

Answer 2

let the time taken until they meet be t hours
distance covered by car A = 32t
distance covered by car B = 64(t-1)

so
32t + 64(t-1) = 512

32t + 64t - 64 = 512
96t = 576
t = 6

draw your conclusion