360 - 315 = 45
so P is 45 degrees north of west from Q
QRP is right angle
so PR = RQ = 60 km
Town P is on bearing 315 degree from town Q. While town R is south of town P and west of town Q. If town R is 60km away from Q, how fara is R from P?
3 answers
My diagram shows a right-angled triangle PQR, with angle Q as 45° and RP = 60
So you have a right-angled isosceles triangle.
No calculations required, RQ is also 60 km
So you have a right-angled isosceles triangle.
No calculations required, RQ is also 60 km
The diagram shows a right angled
360-315=45
SOHCAHTOA
Tan45=x/60
Note: tan45=1
1=x/60
Cross multiply
60*1=x
X=60
360-315=45
SOHCAHTOA
Tan45=x/60
Note: tan45=1
1=x/60
Cross multiply
60*1=x
X=60