The equal and opposite reaction force acts at the same point, so no torque there.
HOWEVER that does NOT mean you can not spin a wheel with a fixed axle.
If you push at rim with force F, the wheel pushes back against your hand with equal and opposite F.
So far no torque to start a a spin.
However so far the net EXTERNAL force on the wheel is F and it would move forward.
SO
if it is not to move forward there must be an equal and opposite force F exerted on the wheel by the bearings at the axle and of course by the axle on the bearings.
Thus net external force = F - F = ZERO
HOWEVER
F at rim forward, and F at axle backward
There is indeed a net Torque now = F * Radius of wheel
Torque is not zero due action and reaction force true or false
2 answers
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