To what volume should you dilute 53 mL of a 12 M stock HNO3

solution to obtain a 0.138 M HNO3
solution?

4 answers

C1V1=C2V2

C1=12 M
V1=53 mL
C2=0.138 M
V2=???

Solve for V2:

V2=(C1*V1)/C2
this isnt correct.
Did you add 53mL to the answer for V2???? Some thinking is required on your part.....V2 is the amount of solvent needed to be added, not the volume you need to add solvent to achieve.
Did you add 53mL to the answer for V2???? Some thinking is required on your part.....V2 is the amount of solvent needed to be added, not the total volume after addition of the solvent.