To what volume should you dilute 131 mL of an 8.20 M CuCl2 solution so that 49.0 mL of the diluted solution contains 4.53g CuCl2 ?
Chemistry...Help!! - Dr Russ, Wednesday, December 8, 2010 at 4:43am
Molar mass of CuCl2 is 134.5 g mol^-1
so solution needs to contain
4.53 g / 134.5 g mol^-1
=0.03368 mole
concentration is
0.049 L/0.03368 mole
=1.455 molar
thus we need to dilute the 8.20 M solution by a factor
8.20 M/1.455 M= 5.636
so the new total volume is
131 ml x 5.636
=738.4 ml
check on the concentration
old solution contains
131 x 8.20 mmoles = 1074 mmoles
new solution contains
1.455 x 738.4 mmole = 1074 mmole
Chemistry...Help!! - Lisa, Help needed!, Wednesday, December 8, 2010 at 1:59pm
Thank you for all the detail, but i'm still confused......so 738.4mL is the answer?
2 answers
It doesn't help us help you if you simply say you are confused without telling us what you understand, what you don't understand, and if possible, why you don't understand.
the second part is moles/volume not volume/moles
1 answer