Asked by Nyle
To what volume should you dilute 124mL of an 8.10M CuCl2 solution so that 49.0mL of the diluted solution contains 4.81g CuCl2?
Molar Mass of CuCl2= 134.45 g/mol
Convert: 4.81g * (1mol/ 13.45g CuCl2)= 0.0358mol CuCl2
[CuCl2]= M= mol/L= (0.0358mol/ 49ml) * (1000mL/1L)= 0.7306M
Dilute the 8.20M of solution by a factor of 0.7306M:
8.20M/ 0.7306M= 11.22
Total Volume= 124mL * 11.22= 1391.73mL
----Where do I go from here to get the final answer?---
Molar Mass of CuCl2= 134.45 g/mol
Convert: 4.81g * (1mol/ 13.45g CuCl2)= 0.0358mol CuCl2
[CuCl2]= M= mol/L= (0.0358mol/ 49ml) * (1000mL/1L)= 0.7306M
Dilute the 8.20M of solution by a factor of 0.7306M:
8.20M/ 0.7306M= 11.22
Total Volume= 124mL * 11.22= 1391.73mL
----Where do I go from here to get the final answer?---
Answers
Answered by
DrBob222
I think you're there if you correct the typo in your next to last step. That 8.20M should be 8.10 M so you get a slightly different factor and that x 124 mL will give you the right answer.
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