The squared distance is sum of squares of difference of all coordinates.
d^2 = (x1-x2)^2 + (y1-y2)^2 = (7-12)^2 + (4-5)^2, so... ;)
To the nearest tenth, what is the distance between (7,4) and (12,5)?
a) 4.8 units
b) 4.9 units
C) 5.0 units
d) 5.1 units
Please explain. Thank you.
4 answers
Thanks!
Welcome ;)
The answer was about 5.1 by the way.