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Let T1,T2,…,Tn be i.i.d. observations, each drawn from a common normal distribution with mean zero. With probability 1/2 this
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Welcome ;)
The squared distance is sum of squares of difference of all coordinates. d^2 = (x1-x2)^2 + (y1-y2)^2 = (7-12)^2 + (4-5)^2, so... ;)
Ca2+ + CO3(2+) = CaCO3 (sediment)
Triangles ABX and ACX are silimar (both have 90 degrees angle, while