To solve 49(3x) = 343(2x+1), write each side of the equation in terms of base what? .

Question

In the brackets are powers.
I tried to solve this but I don't understand I believe it is the first base you go off from but I'm not sure what I'm doing and a reassurance and an explanation would be greatly appreciated.It is solving bases by rewriting bases

Answer 1

I got x=1/2939
But that was incorrect.
Now I believe it's just one

Answer 2

49^3x = 343^(2x+1).
3x*Log49 = (2x+1)*Log343,
Divide both sides by the Log of 49:
3x = (2x+1)*Log343/Log49,
3x = 1.5(2x+1), 3x = 3x+1.5,
3x-3x = 1.5. No solution?

Please make sure the problem is
copied correctly.

Answer 3

49^3x = 343^(x+1),
3x*Log49 = (x+1)*Log343,
Divide both sides by Log49:
3x = (x+1)*Log343/Log49,
3x = 1.5*(x+1),
3x = 1.5x + 1.5,
3x-1.5x = 1.5,
X = 1.

So the 2x in your Eq should be x.

Answer 4

The answer is 7

Answer 5

7 is the answer