Let's go through your questions one by one.
Question 1
To solve the equation \(10 - x^2 = x + 4\), we can rearrange it to equate both sides to zero: \[ 10 - x^2 - x - 4 = 0 \ -x^2 - x + 6 = 0 \ x^2 + x - 6 = 0 \] This can be solved by graphing the following two functions:
- \(f(x) = 10 - x^2\) (the left side)
- \(g(x) = x + 4\) (the right side)
Finding the intersection points of these two graphs will give the solution to the original equation. The solution set is where these two functions equate:
- The correct response is: g(x) = x + 4, f(x) = 10 - x^2, {−3, 2} (indicating the points where the two functions intersect).
Question 2
To solve the equation \(9x - 6 = -8\), we can rearrange it to isolate the variable: \[ 9x - 6 + 6 = -8 + 6 \ 9x = -2 \ x = -\frac{2}{9} \] To graphically find this solution, we should express one side of the equation in terms of \(f(x)\):
- The correct function is: f(x) = 9x - 14 (which expresses the left side of the equation equal to -8).
Question 3
For the equation \(2x - 1 = 4x + 3\), we can solve for \(x\): \[ 2x - 1 - 4x = 3 \ -2x - 1 = 3 \ -2x = 3 + 1 \ -2x = 4 \ x = -2 \] Thus, the solution is: \[ x = -2 \]
Question 4
In this problem:
- Your rate of change (how fast you are walking toward home) is 3 blocks per minute.
- Your starting amount (total distance from your house) is 41 blocks.
- The equation that represents the situation in slope-intercept form can be expressed as: \[ y = -3x + 41 \] where \(y\) is the distance to home and \(x\) is the time in minutes.
To find how long it will take to get home: Setting \(y = 0\) (when you reach home), \[ 0 = -3x + 41 \ 3x = 41 \ x = \frac{41}{3} \approx 13.67 \text{ minutes} \approx 14 \text{ minutes (to the nearest minute)} \]
Summary of Answers
- g(x) = x + 4, f(x) = 10−x^2, {−3, 2}
- f(x) = 9x - 14
- x = -2
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- Your rate of change: 3
- Your starting amount: 41
- Equation in slope-intercept form: \(y = -3x + 41\)
- It will take: 14 minutes