Let's address each question one by one:
Question 1
To solve the equation \(10 - x^2 = x + 4\) by graphing, we first need to rewrite it in the form of two functions:
- \(f(x) = 10 - x^2\) (this is a downward opening parabola)
- \(g(x) = x + 4\) (this is a linear function)
To find the solution, we look for the intersection of these two functions. Setting the equations equal: \[ 10 - x^2 = x + 4. \] Rearranging gives us: \[ x^2 + x - 6 = 0. \] Factoring gives: \[ (x - 2)(x + 3) = 0. \] Thus, the solutions are: \[ x = 2 \quad \text{and} \quad x = -3. \] Answer: \(g(x) = x + 4, f(x) = 10 - x^2, {−3,2}\)
Question 2
To solve \(9x - 6 = -8\), we can rearrange the equation: \[ 9x - 6 + 6 = -8 + 6 \implies 9x = -2. \] Hence, the function to graph is: \[ f(x) = 9x + 2, \] to find the x-value when this equals zero.
Answer: \(f(x) = 9x + 2\)
Question 3
To solve the equation \(2x - 1 = 4x + 3\), rearranging gives: \[ 2x - 4x = 3 + 1 \implies -2x = 4 \implies x = -2. \]
Answer: \(x = -2\)
Question 4
- Your rate of change: 3 (blocks per minute)
- Your starting amount: 41 (blocks)
- Equation: \(y = -3x + 41\) (where \(y\) represents distance remaining)
- To find how long it takes to walk home: \(0 = -3x + 41\): \[ 3x = 41 \implies x = \frac{41}{3} \approx 14 \text{ minutes}. \]
Answer:
- Rate of change: 3
- Starting amount: 41
- Equation: \(y = -3x + 41\)
- Minutes: 14
Question 5
Assuming the tank starts with an initial amount \(A\), at a steady rate of decrease \(r\), then it can be said:
- Starting amount: \(A\)
- Empty after: time \(t\)
- Rate of emptying: \(r\) (you have to provide the numeric values)
- Equation: \(y = A - rt\)
(Specific values would need to be provided to fill in the blanks.)
Question 6
To find the time and distance when Ella catches up, we look at her equation \(y = 6x - 12\) and Brandi's \(y = 4x\). Therefore:
- Answer: Line 1 and Line 2
Question 7
The decay function of a substance that decreases at a rate of 6% is modeled as: \[ f(x) = 600(1 - 0.06)^x = 600(0.94)^x. \]
Answer: \(f(x) = 600(0.94)^x\)
Question 8
For this question, without the specific data provided in your reference, I cannot specify the starting population. Please provide the number or additional data.
Question 9
This scenario represents a parabolic equation because it describes the motion of the ball.
- The maximum height of 30 feet is the vertex point.
- The distance of 60 feet is the x-intercept.
- Axis of symmetry: \(x = 30\).
- The point where the ball starts is \(x = 0\).
Answer: You will need to determine the exact equation using the vertex form or standard form based on data provided.
Question 10
I cannot answer this without additional specifics about the structure of the equation you wish to use for the scenario; please provide more context.
Question 11
To find when \(f(x) = -4.9x^2 + 9\) hits 2 meters, you would solve: \[ -4.9x^2 + 9 = -2 \implies -4.9x^2 + 9 + 2 = 0. \] Rearranging gives: \[ -4.9x^2 + 11 = 0 \implies 4.9x^2 = 11 \implies x^2 = \frac{11}{4.9} \implies x = \sqrt{\frac{11}{4.9}}. \] Calculating this gives the time when the rock hits the bottom.
Question 12
Without specific details on Function 2, I can't determine which function has a greater rate of change. The rate of change is determined by the coefficient of \(x\) in the functions.
Please provide the details needed to answer or clarify, and I can help further!