First determine the M of the concentrated (the 37 %) HCl solution. That is
1000 x 1.19 x 0.37 x (1/36.45) = approx 12 M but you need to do it more exactly.
Then use
mL1 x M1 = mL1 x M2
mL1 x 12M = 1000 mL x 2.5M
Solve for mL1 which is mL of the 37% stuff.
To prepare one liter of 2.5 M solution of HCl, what is the volume of concentrated HCl (37% p/p, d = 1.19 g/mL) to be used?
3 answers
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ens/047/11