It all depends upon what concentration the chemist wants the stock solution. If we call that M, it will be
c1v1 = c2v2
M*5.00L = 18M x v2
substitute M from your problem, which you didn't post, and solve for v2 of the 18.0 M.
(iii) If the chemist wants to prepare 5.00 litres of the stock solution from concentrated H2SO4 , which is 18.0M, what volume of concentrated acid should be used?
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