SOrry this was the first part of the question
To prepare 20 mL of 15 mM NaCl, how much NaCl would you need to weigh
I got 0.021915g
To prepare 5 mL of 1 mM glucose, how much glucose would you need to weigh? How do you prepare
1 mL of 1 mM NaCl using the NaCl solution you prepared in
I get you would use c=n/v and get grams. But how would you answer the second part of the question?
1 answer