52.6*.86=force*.24
solve for force
To leave Nicholson, you exit via the door to the quad. The door is 40 inches wide and has a mass of 200 kg.
You push the door with a perpendicular force of 52.61N exactly 0.86m away from the hinge. This generates the minimum torque, \tau_1, required to open the door.
If you pushed the door 0.24m away from the hinge, with what force (in N) must you push the door to supply the same torque?
1 answer