7.35 = 7.54 + log(base)/(acid)
(base)/(acid) = 0.646
I finally found the problem again. It says you have 500 mL of 0.1M HClO which is 50 mmoles and wants to know how much NaClO would be added.
NaClO/HClO = 0.646
NaClO = 0.646*50 mmols = ??
I would then divide by 1000 to convert to mols.
moles NaClO = grams/molar mass
You know moles NaClO and you know molar mass, solve for grams.
I like to check these things by putting moles NaClO and moles HClO back into the HH equation and see if it gives the correct pH.
to drbob222
ok, the pka (hclo) = 7.54
the ph = 7.35
this problem was under "preparing a buffer" section
1 answer